Splet25. jan. 2024 · Here, the line \ (PQ\) is called the tangent to the circle. As a result, a tangent to a circle is a line that intersects the circle exactly once. This is known as the tangent’s point of contact, and it is at this point, the line is said to meet the circle. Tangent comes from the Latin word tangere, which means “to touch.” SpletTo find the centre of a given circle. Materials Required. A sheet of transparent paper; A geometry box; A bangle; Theory We verified in Activity 19 that the line drawn through the centre of a circle to bisect a chord is perpendicular to the chord. From this it can be deduced that the perpendicular bisector of a chord passes through the centre ...

Math Labs with Activity - Line Drawn through Centre of a Circle to ...

SpletThe line drawn from the centre of a circle perpendicular to a chord line from centre to chord bisects the chord. ... In the figure PR and PQ are two tangents drawn from point P to circle AQR. The straight. line drawn through P parallel to AR meets QR produced at S, and QA produced at T. The tangent PR cuts QT at B. Let R̂ 2 = x. Splet08. feb. 2024 · In the picture, a circle is drawn with a line as diameter and a smaller circle with half the line as diameter. Prove that any chord of the larger circle through the point where the circles meet is bisected by the small circle. Answer: ∠ADO = ∠APB = 90° (angle subtended by diameter is always 90°) ⇒ OD\\PB AO = OB (Radius of bigger circle) high rated apartments denver

in the given figure, EF is a line passing through the centre o of a ...

Splet07. apr. 2024 · A chord is the line segment that joins two different points of the circle which can also pass through the centre of the circle. If a chord passes through the centre of the circle, then it becomes diameter. Suppose, here we consider d as the diameter, then the radius is given by d = r/2 The diameter of the circle is the longest chord. SpletTheorem 2: The line drawn through the centre of the circle to bisect a chord is perpendicular to the chord. Given: The circle's chord AB has its midpoint at C, with the circle's centre at O. To prove: OC⊥AB. Construction: Join … Splet∠A = 180° – 60° – 90° = 120° – 90° = 30° Also, we know that the tangent at any point of a circle is perpendicular to the radius through the point of contact ∴ ∠ABC = 90° Now, In ΔABC, ∠C = 180° – ∠A – ∠B = 180° – 30° – 90° = 150° – 90° = 60° Concept: Tangent to a Circle Report Error Is there an error in this question or solution? how many calories in 1 lb of watermelon